#![allow(clippy::uninlined_format_args)] use criterion::{criterion_group, criterion_main, BenchmarkId, Criterion}; const CODES: &[u16] = &[0, 1000, 201, 800, 550]; fn bench_quality_display_impls(c: &mut Criterion) { let mut group = c.benchmark_group("quality value display impls"); for i in CODES.iter() { group.bench_with_input(BenchmarkId::new("New (fast?)", i), i, |b, &i| { b.iter(|| _new::Quality(i).to_string()) }); group.bench_with_input(BenchmarkId::new("Naive", i), i, |b, &i| { b.iter(|| _naive::Quality(i).to_string()) }); } group.finish(); } criterion_group!(benches, bench_quality_display_impls); criterion_main!(benches); mod _new { use std::fmt; pub struct Quality(pub(crate) u16); impl fmt::Display for Quality { fn fmt(&self, f: &mut fmt::Formatter<'_>) -> fmt::Result { match self.0 { 0 => f.write_str("0"), 1000 => f.write_str("1"), // some number in the range 1–999 x => { f.write_str("0.")?; // this implementation avoids string allocation otherwise required // for `.trim_end_matches('0')` if x < 10 { f.write_str("00")?; // 0 is handled so it's not possible to have a trailing 0, we can just return itoa_fmt(f, x) } else if x < 100 { f.write_str("0")?; if x % 10 == 0 { // trailing 0, divide by 10 and write itoa_fmt(f, x / 10) } else { itoa_fmt(f, x) } } else { // x is in range 101–999 if x % 100 == 0 { // two trailing 0s, divide by 100 and write itoa_fmt(f, x / 100) } else if x % 10 == 0 { // one trailing 0, divide by 10 and write itoa_fmt(f, x / 10) } else { itoa_fmt(f, x) } } } } } } pub fn itoa_fmt(mut wr: W, value: V) -> fmt::Result { let mut buf = itoa::Buffer::new(); wr.write_str(buf.format(value)) } } mod _naive { use std::fmt; pub struct Quality(pub(crate) u16); impl fmt::Display for Quality { fn fmt(&self, f: &mut fmt::Formatter<'_>) -> fmt::Result { match self.0 { 0 => f.write_str("0"), 1000 => f.write_str("1"), x => { write!(f, "{}", format!("{:03}", x).trim_end_matches('0')) } } } } }