notes/school/di-ma/uebung/09/09_4.tex
Valentin Brandl f5a3d1719e
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Add solution for dima 9
2018-12-18 15:19:25 +01:00

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\documentclass[12pt,a4paper,german]{article}
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%%%%%%%%%% Fill out the the definitions %%%%%%%%%
\def \name {Valentin Brandl} %
\def \matrikel {108018274494} %
\def \pname {Marvin Herrmann} %
\def \pmatrikel {108018265436} %
\def \gruppe {2 (Mi 10-12 Andre)}
\def \qname {Pascal Brackmann}
\def \qmatrikel {108017113834} %
\def \uebung {9} %
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% DO NOT MODIFY THIS HEADER
\newcommand{\hwsol}{
\vspace*{-2cm}
\noindent \matrikel \quad \name \hfill \"Ubungsgruppe: \gruppe \\
\noindent \pmatrikel \quad \pname \\
\noindent \qmatrikel \quad \qname \\
\begin{center}{\Large \bf L\"osung f\"ur \"Ubung \# \uebung}\end{center}
}
\begin{document}
%Import header
\hwsol
\section*{Aufgabe 9.4}
\begin{itemize}[1.]
\item
\begin{align*}
15 * x &\equiv 6 &\mod 84 \\
\\
4 &= 2 * 84 - 11 * 15 \\
1 &= 2 * 28 - 11 * 5 \\
\Rightarrow x &= (-11) * 2 &\mod 84 \\
x &= (-11) * 2 + j * 28 \text{ mit } j \in \mathbb{Z} \\
\\
15 * 6 = 90 &\equiv 6 &\mod 84
\end{align*}
\item
\begin{align*}
32 * x &\equiv 2 &\mod 93 \\
\\
1 &= 32 * 32 - 11 * 93 \\
\Rightarrow x &= 32 * 2 &\mod 93 \\
x &= 32 * 2 + j * 93 \text{ mit } j \in \mathbb{Z} \\
\\
32 * (-29) = -928 &\equiv 2 &\mod 93
\end{align*}
\end{itemize}
\end{document}