notes/school/di-ma/uebung/09/09_3.tex
Valentin Brandl f5a3d1719e
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Add solution for dima 9
2018-12-18 15:19:25 +01:00

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\documentclass[12pt,a4paper,german]{article}
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%%%%%%%%%% Fill out the the definitions %%%%%%%%%
\def \name {Valentin Brandl} %
\def \matrikel {108018274494} %
\def \pname {Marvin Herrmann} %
\def \pmatrikel {108018265436} %
\def \gruppe {2 (Mi 10-12 Andre)}
\def \qname {Pascal Brackmann}
\def \qmatrikel {108017113834} %
\def \uebung {9} %
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\newcommand{\hwsol}{
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\noindent \matrikel \quad \name \hfill \"Ubungsgruppe: \gruppe \\
\noindent \pmatrikel \quad \pname \\
\noindent \qmatrikel \quad \qname \\
\begin{center}{\Large \bf L\"osung f\"ur \"Ubung \# \uebung}\end{center}
}
\begin{document}
%Import header
\hwsol
\section*{Aufgabe 9.3}
\begin{enumerate}[1.]
\item
\begin{tabular}{|c|c|c|}
\hline
$eea(a,b)$ & $(d',x',y')$ & $(d,x,y)$ \\\hline\hline
$eea(84,15)$ & $(3,-1,2)$ & $(3,2,-11)$ \\\hline
$eea(15,9)$ & $(3,1,-1)$ & $(3,-1,2)$ \\\hline
$eea(9,6)$ & $(3,0,1)$ & $(3,1,-1)$ \\\hline
$eea(6,3)$ & $(3,1,0)$ & $(3,0,1)$ \\\hline
$eea(3,0)$ & & $(3,1,0)$ \\\hline
\end{tabular}
$ggt(84,15) = 84 * 2 + 15 * (-11) = 3$
\item
\begin{tabular}{|c|c|c|}
\hline
$eea(a,b)$ & $(d',x',y')$ & $(d,x,y)$ \\\hline\hline
$eea(93,32)$ & $(1,10,-11)$ & $(1,-11,32)$ \\\hline
$eea(32,29)$ & $(1,-1,10)$ & $(1,10,-11)$ \\\hline
$eea(29,3)$ & $(1,1,-1)$ & $(1,-1,10)$ \\\hline
$eea(3,2)$ & $(1,0,1)$ & $(1,1,-1)$ \\\hline
$eea(2,1)$ & $(1,1,0)$ & $(1,0,1)$ \\\hline
$eea(1,0)$ & & $(1,1,0)$ \\\hline
\end{tabular}
$ggt(93,32) = 93 * (-11) + 32 * 32 = 1$
\end{enumerate}
\end{document}